-4.9x^2+5x+1.2=0

Solution for -4.9x^2+5x+1.2=0 equation:

-4.9x^2+5x+1.2=0

a = -4.9; b = 5; c = +1.2;
Δ = b2-4ac
Δ = 52-4·(-4.9)·1.2
Δ = 48.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{48.52}}{2*-4.9}=\frac{-5-\sqrt{48.52}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{48.52}}{2*-4.9}=\frac{-5+\sqrt{48.52}}{-9.8}
$